2011-02-20 23:16:05 +01:00
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package org.bukkit.craftbukkit;
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/**
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2011-02-20 23:22:28 +01:00
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* Credits for this class goes to user aioobe on stackoverflow.com
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* Source: http://stackoverflow.com/questions/4454630/j2me-calculate-the-the-distance-between-2-latitude-and-longitude
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2011-02-20 23:16:05 +01:00
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*
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*/
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public class TrigMath {
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static final double sq2p1 = 2.414213562373095048802e0;
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static final double sq2m1 = .414213562373095048802e0;
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static final double p4 = .161536412982230228262e2;
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static final double p3 = .26842548195503973794141e3;
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static final double p2 = .11530293515404850115428136e4;
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static final double p1 = .178040631643319697105464587e4;
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static final double p0 = .89678597403663861959987488e3;
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static final double q4 = .5895697050844462222791e2;
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static final double q3 = .536265374031215315104235e3;
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static final double q2 = .16667838148816337184521798e4;
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static final double q1 = .207933497444540981287275926e4;
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static final double q0 = .89678597403663861962481162e3;
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static final double PIO2 = 1.5707963267948966135E0;
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private static double mxatan(double arg) {
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double argsq = arg * arg, value;
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2011-06-12 01:12:43 +02:00
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2011-02-20 23:16:05 +01:00
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value = ((((p4 * argsq + p3) * argsq + p2) * argsq + p1) * argsq + p0);
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2011-06-12 01:12:43 +02:00
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value = value / (((((argsq + q4) * argsq + q3) * argsq + q2) * argsq + q1) * argsq + q0);
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2011-02-20 23:16:05 +01:00
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return value * arg;
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}
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private static double msatan(double arg) {
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return arg < sq2m1 ? mxatan(arg)
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: arg > sq2p1 ? PIO2 - mxatan(1 / arg)
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: PIO2 / 2 + mxatan((arg - 1) / (arg + 1));
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}
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public static double atan(double arg) {
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return arg > 0 ? msatan(arg) : -msatan(-arg);
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}
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public static double atan2(double arg1, double arg2) {
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if (arg1 + arg2 == arg1)
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return arg1 >= 0 ? PIO2 : -PIO2;
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arg1 = atan(arg1 / arg2);
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return arg2 < 0 ? arg1 <= 0 ? arg1 + Math.PI : arg1 - Math.PI : arg1;
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}
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}
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